lab01_group24_final

lab01_group24_final/backward_solve.m

-function R1 = backward_solve(A1)
-
-m = size(A1,1);
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-n = size(A1,2);
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-c = m*n;
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-B = zeros(c,c);
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-for i = 1:c
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-	for j= 1:c
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-		k1=(i-1-mod(i-1,n))/n;
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-		k2=(1+mod(i-1,n));
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-		l1=(j-1-mod(j-1,n))/n;
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-		l2=(1+mod(j-1,n));
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-		if(((abs(k1-l1)==0)&&(abs(k2-l2)==1))||((abs(k1-l1)==1)&&(abs(k2-l2)==0))) 
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-			B(i,j) = 1;
-
-		end
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-		if((k1==l1)&&(k2==l2))
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-			B(i,j) = 1;
-
-		end
-
-	end
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-end
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-R = zeros(1,c);
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-A = zeros(1,c);
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-for i = 1:m
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-	for j=1:n
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-		A(1,(((i-1)*n)+j)) = A1(i,j); 
-
-	end
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-end
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-R = (A*(B^(-1))).*det(B);
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-R = abs(R);
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-R = int64(R);
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-R = mod(R,2);
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-R1 = zeros(m,n);
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-for i = 1:m
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-	for j=1:n
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-		 R1(i,j) = R(1,(((i-1)*n)+j)); 
-
-	end
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-end
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-return 
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-endfunction
-
-
-

lab01_group24_final/backward_solve_3.m

-function R1 = backward_solve_3(A1)
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-L = [1 1 0; 1 1 1; 0 1 1 ];
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-M = [1 0 0; 0 1 0; 0 0 1 ];
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-N = zeros(3,3);
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-B = [L M N; M L M; N M L ];
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-A = [A1(1, :) A1(2, :) A1(3, :)];
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-R = zeros(1,9);
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-X = [0 0 1 1 0 1 0 1 1 ];
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-%R = mod(A + X*B,2);
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-%R = A/B;
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-%R = (A + X*B);
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-R = (A*(B^(-1))).*det(B);
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-R = abs(R);
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-R = int64(R);
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-R = mod(R,2);
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-R1 = zeros(3,3);
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-R1 = [R(1,1:3); R(1,4:6); R(1,7:9)];
-
-return
-
-endfunction
-
-%disp(A)
-
-%disp(B)
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lab01_group24_final/input_outlab_task_A1.txt

-180.0 100 0.05 5 3.5
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lab01_group24_final/input_outlab_task_A2.txt

-0.0 0.0 76.63 27 0.027 0.0555 7 5 3.5 5
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lab01_group24_final/main_task_A1.m

-clear; clc;
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-file1 = fopen('input_outlab_task_A1.txt');
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-A = fscanf(file1, '%f', [5,1]);
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-fclose(file1);
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-f = @ (a) (((A(2)-A(4))*tan(a)) + (A(4)*sin(a))/(sqrt((A(5))^2-((sin(a))^2))) - A(1));
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-theta = fzero(f,[0,1.5]);
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-theta = theta * (180/pi);
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-file2 = fopen('output_outlab_task_A1.txt','w');
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-fprintf(file2, '%f', theta);
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-fclose(file2);
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lab01_group24_final/main_task_A2.m

-clear; clc;
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-file1 = fopen('input_outlab_task_A2.txt');
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-A = fscanf(file1, '%f', [10,1]);
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-fclose(file1);
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-x1 = A(3) - A(1);
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-y1 = A(4) - A(2);
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-%secr = A(9)/((sqrt((A(9))^2-((sin(a))^2))));
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-%a1 = (((sec(a))*(y1-A(8))) + ((A(9)/((sqrt((A(9))^2-((sin(a))^2)))))*(A(8))) + ((sec(a))*(A(5))*(A(10))))/(A(6)-(A(5)*(sec(a))));
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-f = @ (a) ((A(5)*(A(10)+ ( ( ((sec(a))*(y1-A(8))) + (((A(9)/((sqrt((A(9))^2-((sin(a))^2)))))*(A(8)))*A(9)) + ((sec(a))*(A(5))*(A(10))) ) / (A(6)-(A(5)*(sec(a)))) ) )*tan(a)) + ((y1-A(8))*tan(a)) + ((A(8)*sin(a))/(sqrt((A(9))^2-((sin(a))^2)))) - x1) ;
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-theta = fzero(f,[0.1,1.0]);
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-A(10) = 3*A(10);
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-a3 = (((sec(theta))*(y1-A(8))) + (((A(9)/((sqrt((A(9))^2-((sin(theta))^2)))))*(A(8)))*A(9)) + ((sec(theta))*(A(5))*(A(10))))/(A(6)-(A(5)*(sec(theta))));
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-xf = x1;
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-yf = y1 + (3*A(10)+a3)*A(5);
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-theta = theta * (180/pi);
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-%disp(theta)
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-%disp(yf)
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-file2 = fopen('output_outlab_task_A2.txt','w');
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-fprintf(file2, '%f %f %f', theta, xf, yf);
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-fclose(file2);
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lab01_group24_final/output_outlab_task_A1.txt

-62.003645
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lab01_group24_final/output_outlab_task_A2.txt

-41.070190 76.630000 93.409613
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lab01_group24_final/readme.txt

-GROUP NUMBER - 24
-(150050071, Aahwan), (150050072, Sai Teja), (150050079, Rathod Dinesh).
-150050071- 100%
-150050072- 100%
-150050079- 100%
-Comments on the code :
-
-	-Task A2 had an important point. The consideration that laser travels with a velocity equal to velocity/refractiveIndex in the medium.
-
-	-There was a bit of an ambiguity in the task A2 description.Strictly considering the meaning, actually the second angle must be taken(because it is mentioned: to destroy the shield and it takes 2 hits to destroy it). But since the answer given is the angle for the first laser beam, the code for the same has been written.  
-
-	-An interesting pattern was observed for the action matrix for the general case of backward solve but that wasn't implemented because of the ease of generation using loops was more.
-
-Honour code :
-
-	We pledge on our honour that we have not given or received any unauthorized assistance on this assignment or any previous task.
-
-							-(150050071, Aahwan), (150050072, Sai Teja), (150050079, Rathod Dinesh).
-
-Citations :
-	
-	Octave learnt and understood from :
-
-	https://www.youtube.com/watch?v=gkVOSxmhtyk&index=17&list=PLHj4uM4X8Oso_M2yN6Fg0_Mp219z6f5-W
-		
-Reflection essay :
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-	In the lights out problem found a pattern for the action matrix for different m*n matrices.
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-	Solved the interesting problem of two spaceships.
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-	Realised the point that laser travels with a velocity equal to velocity/refractive index in the medium!(that eureka moment :)) 
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