Commit c5c97318 authored by Tom Lane's avatar Tom Lane

In find_mergeclauses_for_pathkeys, it's okay to return multiple merge

clauses per path key.  Indeed, we *must* do so or we will be unable to
form a valid plan for FULL JOIN with overlapping join conditions, eg
select * from a full join b on
a.v1 = b.v1 and a.v2 = b.v2 and a.v1 = b.v2.
parent c336b58f
......@@ -11,7 +11,7 @@
* Portions Copyright (c) 1994, Regents of the University of California
*
* IDENTIFICATION
* $Header: /cvsroot/pgsql/src/backend/optimizer/path/pathkeys.c,v 1.35 2001/10/28 06:25:44 momjian Exp $
* $Header: /cvsroot/pgsql/src/backend/optimizer/path/pathkeys.c,v 1.36 2001/11/11 20:33:53 tgl Exp $
*
*-------------------------------------------------------------------------
*/
......@@ -752,25 +752,43 @@ find_mergeclauses_for_pathkeys(Query *root,
List *mergeclauses = NIL;
List *i;
/* make sure we have pathkeys cached in the clauses */
foreach(i, restrictinfos)
{
RestrictInfo *restrictinfo = lfirst(i);
cache_mergeclause_pathkeys(root, restrictinfo);
}
foreach(i, pathkeys)
{
List *pathkey = lfirst(i);
RestrictInfo *matched_restrictinfo = NULL;
List *matched_restrictinfos = NIL;
List *j;
/*
* We can match a pathkey against either left or right side of any
* mergejoin clause we haven't used yet. For the moment we use a
* dumb "greedy" algorithm with no backtracking. Is it worth
* being any smarter to make a longer list of usable mergeclauses?
* Probably not.
* mergejoin clause. (We examine both sides since we aren't told if
* the given pathkeys are for inner or outer input path; no confusion
* is possible.) Furthermore, if there are multiple matching
* clauses, take them all. In plain inner-join scenarios we expect
* only one match, because redundant-mergeclause elimination will
* have removed any redundant mergeclauses from the input list.
* However, in outer-join scenarios there might be multiple matches.
* An example is
*
* select * from a full join b on
* a.v1 = b.v1 and a.v2 = b.v2 and a.v1 = b.v2;
*
* Given the pathkeys ((a.v1), (a.v2)) it is okay to return all
* three clauses (in the order a.v1=b.v1, a.v1=b.v2, a.v2=b.v2)
* and indeed we *must* do so or we will be unable to form a
* valid plan.
*/
foreach(j, restrictinfos)
{
RestrictInfo *restrictinfo = lfirst(j);
cache_mergeclause_pathkeys(root, restrictinfo);
/*
* We can compare canonical pathkey sublists by simple pointer
* equality; see compare_pathkeys.
......@@ -779,8 +797,8 @@ find_mergeclauses_for_pathkeys(Query *root,
pathkey == restrictinfo->right_pathkey) &&
!ptrMember(restrictinfo, mergeclauses))
{
matched_restrictinfo = restrictinfo;
break;
matched_restrictinfos = lappend(matched_restrictinfos,
restrictinfo);
}
}
......@@ -789,14 +807,14 @@ find_mergeclauses_for_pathkeys(Query *root,
* sort-key positions in the pathkeys are useless. (But we can
* still mergejoin if we found at least one mergeclause.)
*/
if (!matched_restrictinfo)
if (matched_restrictinfos == NIL)
break;
/*
* If we did find a usable mergeclause for this sort-key position,
* add it to result list.
* If we did find usable mergeclause(s) for this sort-key position,
* add them to result list.
*/
mergeclauses = lappend(mergeclauses, matched_restrictinfo);
mergeclauses = nconc(mergeclauses, matched_restrictinfos);
}
return mergeclauses;
......
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